Spence, not wanting to be disagreeable in spite of whatever Nick thinks
, the reasoning behind your solution doesn't make a whole lot of sense to me.
You say you want to keep the "pot" in $5 increments, but what do you do if the SB folds? Does that $2 count as part of the "pot"? It certainly isn't a "full bet". I can understand the solution, but I just can't understand why you count "this $2, but not that $2". I am not a PLO expert, but it seems to me from my Hold'em experience that having an odd $2 because the SB folds occurs much more often than having an odd $2 because of dead money, regardless of the reason (Buy the Button, Player returns from absence and has to post missed blinds, etc.)
Chet